論壇里又有人問起日期怎樣格式化為:2004-08-09 05:02:20這樣的格式:于是寫了一個左(右)對齊的函數.這函數等價于.NET里String對象的PadLeft和PadRight函數

Function PadLeft(Value,Length,sChar)
  Dim strText,I
  strText = String(Length,sChar)
  strText = strText & Value
  LeftPad = Right(strText,Length)
End Function

改一下最下面則為這樣:

Function PadRight(Value,Length,sChar)
  Dim strText,I
  strText = String(Length,sChar)
  strText = Value & strText
  LeftPad = Left(strText,Length)
End Function

使用例子:日期顯示

AA = year(now) & "-" & PadLeft(month(now),2,"0") & "-" & PadLeft(Day(now),2,"0") & " " & PadLeft(Hour(now),2,"0") & ":" & PadLeft(Minute(now),2,"0") & ":" & PadLeft(Second(now),2,"0")

萬能時間補位代碼

Public Function ForMatDate(DateAndTime, Para) "格式化日期(日期時間,格式) 
Dim Y, M, D, H, F, S 
IF Not ISNumeric(Para) Or Not ISDate(DateAndTime) Then Exit Function 
Y = CStr(Year(DateAndTime)) 
M = CStr(Month(DateAndTime)):IF Len(M) = 1 Then M = "0" & M 
D = CStr(Day(DateAndTime)):IF Len(D) = 1 Then D = "0" & D 
H = CStr(Hour(DateAndTime)):IF Len(H) = 1 Then H = "0" & H 
F = CStr(Minute(DateAndTime)):IF Len(F) = 1 Then F = "0" & F 
S = CStr(Second(DateAndTime)):IF Len(S) = 1 Then S = "0" & S 
Select Case Para 
  Case "0" 
    ForMatDate = Y & "-" & M & "-" & D & " " & H & ":" & F & ":" & S 
  Case "1" 
    ForMatDate = Y & "-" & M & "-" & D & " " & H & ":" & F 
  Case "2" 
    ForMatDate = Y & "-" & M & "-" & D 
  Case "3" 
    ForMatDate = Y & "/" & M & "/" & D 
  Case "4" 
    ForMatDate = Y & "年" & M & "月" & D & "日" 
  Case "5" 
    ForMatDate = M & "-" & D & " " & H & ":" & F 
  Case "6" 
    ForMatDate = M & "/" & D 
  Case "7" 
    ForMatDate = M & "月" & D & "日" 
  Case "8" 
    ForMatDate = Y & "年" & M & "月" 
  Case "9" 
    ForMatDate = Y & "-" & M 
  Case "10" 
    ForMatDate = Y & "/" & M 
  Case "11" 
    ForMatDate = right(Y,2) & "-" &M & "-" & D & " " & H & ":" & F 
  Case "12" 
    ForMatDate = right(Y,2) & "-" &M & "-" & D 
  Case "13" 
    ForMatDate = M & "-" & D 
  Case Else 
    ForMatDate = DateAndTime 
End Select 
End Function 
Response.Write ForMatDate(Now,"2")

asp一段自動補位的函數

function formatsn(getnum,getbit)
dim formatsnnum,formatsnpre,formatsnj
formatsnnum = getbit – len(getnum)
for formatsnj = 1 to formatsnnum
formatsnpre = formatsnpre & "0"
next
formatsn = formatsnpre & getnum
end function

使用方法

formatsn(getnum,getbit)

getnum 計數
getbit 共幾位

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